给定一系列正整数，请按要求对数字进行分类，并输出以下 5 个数字：

A1 = 能被 5 整除的数字中所有偶数的和；

A2 = 将被 5 除后余 1 的数字按给出顺序进行交错求和，即计算 n1−n2+n3−n4⋯；

A3 = 被 5 除后余 2 的数字的个数；

A4 = 被 5 除后余 3 的数字的平均数，精确到小数点后 1 位；

A5 = 被 5 除后余 4 的数字中最大数字。

输入格式：

每个输入包含 1 个测试用例。每个测试用例先给出一个不超过 1000 的正整数 N，随后给出 N 个不超过 1000 的待分类的正整数。数字间以空格分隔。

输出格式：

对给定的 N 个正整数，按题目要求计算 A1~A5 并在一行中顺序输出。数字间以空格分隔，但行末不得有多余空格。

若其中某一类数字不存在，则在相应位置输出 N。

输入样例 1：

13 1 2 3 4 5 6 7 8 9 10 20 16 18

输出样例 1：

30 11 2 9.7 9

输入样例 2：

8 1 2 4 5 6 7 9 16

输出样例 2：

N 11 2 N 9

编程语言：Python

解题思想：

1.逐个判断，添加到对应列表

2.对列表长度进行判断，进行后续操作

时间复杂度：O(N)

代码如下：

Number = list(map(int, input().split()))
 
A1 = list()
A2 = list()
A3 = list()
A4 = list()
A5 = list()
for content in Number[1:]:
    value = content % 5
    if value == 0 and content % 2 == 0:
        A1.append(content)
    elif value == 1:
        A2.append(content)
    elif value == 2:
        A3.append(content)
    elif value == 3:
        A4.append(content)
    elif value == 4:
        A5.append(content)
 
if len(A1) != 0:
    A1 = sum(A1)
else:
    A1 = 'N'
 
if len(A2) != 0:
    StaggeredSum = 0
    for i in range(len(A2)):
        StaggeredSum += ((-1) ** i) * A2[i]
    A2 = StaggeredSum
else:
    A2 = 'N'
 
if len(A3) != 0:
    A3 = len(A3)
else:
    A3 = 'N'
 
if len(A4) != 0:
    A4 = round(sum(A4) / len(A4), 1)
else:
    A4 = 'N'
 
if len(A5) != 0:
    A5 = max(A5)
else:
    A5 = 'N'
 
print(A1, A2, A3, A4, A5)

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PAT乙级:1012 数字分类