描述

反转一个只有3位数的整数。

Tips: 你可以假设输入一定是一个只有三位数的整数，这个整数大于等于100，小于1000。

样例

样例1

输入: number = 123
输出: 321

样例2

输入: number = 900
输出: 9

编程语言：Java

解题思想：

1.使用Java的字符串类库。

2.字符串与整型的互相转换。

3.字符串的拼接。

时间复杂度：O(1)

IDE代码如下：

package Lintcode;
 
import java.util.Scanner;
 
public class _37 {
 
	public static void main(String[] args) {
		Scanner scanner = new Scanner(System.in);
		int Number = scanner.nextInt();
		int ChangeNumber;
		ChangeNumber=Integer.parseInt((Number+"").charAt(2)+""+(Number+"").charAt(1)+""+(Number+"").charAt(0)+"");
		System.out.println(ChangeNumber);
	}
 
}

LintCode编辑器代码如下：

public class Solution {
 
    public int reverseInteger(int number) {
		int ChangeNumber;
		ChangeNumber=Integer.parseInt((number+"").charAt(2)+""+(number+"").charAt(1)+""+(number+"").charAt(0)+"");
		return ChangeNumber;
    }
}

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LintCode_naive:反转一个3位整数

描述

样例