要获得一个 C 语言程序的运行时间，常用的方法是调用头文件 time.h，其中提供了 clock() 函数，可以捕捉从程序开始运行到 clock() 被调用时所耗费的时间。这个时间单位是 clock tick，即“时钟打点”。同时还有一个常数 CLK_TCK，给出了机器时钟每秒所走的时钟打点数。于是为了获得一个函数 f 的运行时间，我们只要在调用 f 之前先调用 clock()，获得一个时钟打点数 C1；在 f 执行完成后再调用 clock()，获得另一个时钟打点数 C2；两次获得的时钟打点数之差 (C2-C1) 就是 f 运行所消耗的时钟打点数，再除以常数 CLK_TCK，就得到了以秒为单位的运行时间。

这里不妨简单假设常数 CLK_TCK 为 100。现给定被测函数前后两次获得的时钟打点数，请你给出被测函数运行的时间。

输入格式：

输入在一行中顺序给出 2 个整数 C1 和 C2。注意两次获得的时钟打点数肯定不相同，即 C1 < C2，并且取值在 [0,107]。

输出格式：

在一行中输出被测函数运行的时间。运行时间必须按照 hh:mm:ss（即2位的 时:分:秒）格式输出；不足 1 秒的时间四舍五入到秒。

输入样例：

123 4577973

输出样例：

12:42:59

编程语言：Python

解题思想：

1.思考一个算法，提供秒，可以得到对应的小时数、分钟数、秒数

2.对秒数进行四舍五入

3.不足2位的输出需要补0

时间复杂度：O(1)

代码如下：

Start, End = map(int, input().split())  # 输入起始和结束时间
 
# 获取小时、分钟、秒的算法，/100的打点常数获得具体的秒数
Hour = int((End - Start) / 100 / 3600)
Minute = int((End - Start) / 100 % 3600 / 60)
Seconds = (End - Start) / 100 % 3600 % 60
 
if Seconds - int(Seconds) >= 0.5:  # 实现四舍五入，例如42.6秒，通过int转换后为42秒
    Seconds += int(Seconds) + 1  # 转为43秒
 
# 补足0，例如1:26:3需要补足为01:26:03
Hour = (2 - len(str(Hour) + '')) * '0' + str(Hour)
Minute = (2 - len(str(Minute) + '')) * '0' + str(Minute)
Seconds = (2 - len(str(Seconds) + '')) * '0' + str(Seconds)
 
print(Hour + ':' + Minute + ':' + Seconds + '')

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PAT乙级:1026 程序运行时