当自然数 n 依次取 1、2、3、……、N 时，算式 ⌊n/2⌋+⌊n/3⌋+⌊n/5⌋ 有多少个不同的值？（注：⌊x⌋ 为取整函数，表示不超过 x的最大自然数，即 x 的整数部分。）

输入格式：

输入给出一个正整数 N（2≤N≤104）。

输出格式：

在一行中输出题面中算式取到的不同值的个数。

输入样例：

输出样例：

编程语言：Python

解题思想：

1.利用int进行取整

2.利用Python中set的性质进行去重

时间复杂度：O(N)

代码如下：

N = int(input())
Value = list()  # 存放每个算式的值
for i in range(1, N + 1):
    Value.append(int(i / 2) + int(i / 3) + int(i / 5))  # 将算式的值添加到列表中
 
Value = set(Value)  # 将列表转为集合，这样可以去除重复的值
print(len(Value))  # 集合的长度就是算式取到的不同值的个数

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PAT乙级:1087 有多少不同的值

输入格式：

输出格式：

输入样例：

输出样例：

编程语言：Python

解题思想：

时间复杂度：O(N)

代码如下：

评论板

共有 7 条评论

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